Question

Ex:3 Cine ma poate ajuta, ii dau coroana ​

Answer 1

Răspuns: Rezolvarea e mai jos

Explicație pas cu pas:

Salutare!

$\bf a)~ 8x\cdot(2x-1)-6\cdot(2x-1)=$

$\bf (2x-1)\cdot(8x-6)=$

$\boxed{\bf 2\cdot(2x-1)\cdot(4x-3)}$

$\it~~~$

$\bf b)~ (3x+1)^{2}-5x\cdot(3x+1)-(3x+1)=$

$\bf (3x+1)\cdot[(3x+1)-5x-1]=$

$\bf (3x+1)\cdot(3x+1-5x-1)=$

$\boxed{\bf -2x\cdot (3x+1)}$

$\it~~$

$\bf c)~ (x-1)\cdot(2x+3)-(x-1)\cdot(5x-1)=$

$\bf (x-1)\cdot[(2x+3)-(5x-1)]=$

$\bf (x-1)\cdot(2x+3-5x+1)=$

$\boxed{\bf (x-1)\cdot(4-3x)}$

$\it~~$

$\bf d)~ 3x\sqrt{2}\cdot(2x+1)+5\sqrt{2}\cdot(2x+1)-7x^{2} \sqrt{2}\cdot(2x+1)=$

$\boxed{\bf \sqrt{2}\cdot(2x+1)\cdot(3x+5-7x^{2} )}$

==pav38==