Question

Ex 3 punctul E DAU COROANAA

Answer 1

Explicație pas cu pas:

e) Mai intai desfacem parantezele:

x³-5x²+2x-7-(x³+4x-1)+(x²+6x+2)=

=x³-5x²+2x-7-x³-4x+1+x²+6x+2=

=x³-x³-5x²+x²+2x-4x+6x+1+2-7=

=0-4x²+4x-4=

=4(-x²+x-1)

Answer 2

Explicație pas cu pas:

${x}^{3} - 5 {x}^{2} + 2x - 7 - {x}^{3} - 4x + 1 + {x}^{2} + 6x + 2 =$

$= ({x}^{3} - {x}^{3}) + ( - 5 {x}^{2} + {x}^{2}) + (2x - 4x + 6x) + (- 7 + 1 + 2)$

$= 0 + ( - 4 {x}^{2} ) + (8x - 4x) + ( - 7 + 3)$

$= - 4 {x}^{2} + 4x - 4 = \bf - 4( {x}^{2} - x + 1)$