Question

Ex 3 rapid ajutor am nevoie va rog!

Answer 1

In genul acesta de exercitiu inmultim termenii pe diagonala si tinem cont de distributivitate a*(b+c)=a*b + a*c:

$\frac{a+b}{2a+5b}=\frac{1}{3}\\\\3a+3b=2a+5b\\3a-2a=5b-3b\\a=2b\\\frac{a}{b}=2$

$\frac{2a+3b}{a+4b}=\frac{3}{2}\\\\4a+6b=3a+12b\\4a-3a=12b-6b\\a=6b\\\frac{a}{b}=6$

$\frac{a-b}{a+b}=\frac{1}{3}\\\\3a-3b=a+b\\3a-a=3b+b\\2a=4b\\a=2b\\\frac{a}{b}=2$

$\frac{3a-4b}{2a-3b}=\frac{2}{3}\\\\9a-12b=4a-6b\\9a-4a=12b-6b\\5a=6b\\\frac{a}{b}=\frac{6}{5}$