Question

ex 3 va rog dau cororana!​

Answer 1

2^(2x+1) - 3 * 2^x + 1 = 0

(2^x)^2 * 2 - 3 * 2^x + 1 = 0

Notezi t = 2^x

2t² - 3t + 1 = 0

delta = 9 - 8 = 1

t₁ = (3+1)/4 = 4/4 = 1

t₂ = (3-1)/4 = 2/4 = 1/2

Din t = 2^x

=> 2^x = 1 => 2^x = 2^0 => x = 0

=> 2^x = 1/2 => 2^x = 2^(-1) => x = -1