Question

ex.5 daca ma-ti ajuta vas fi recunoscatoare chiar daca nu va cunosc!!

Answer 1

a) 37/10*x=0,2*[30*(2int.2/3+3,5)]
37x/10=0,2*30*(8/3+35/10)
37x/10=0,2*30*(80/30+105/30)
37x/10=0,2*30*185/30
37x/10=0,2*185
3,7x=37
x=37/3,7
x=10
b)5/24*x=1,2*(2,5-1 int 2/3)^2
5x/24=1,2*(25/10-5/3)^2
5x/24=1,2*(75/30-50/30)^2
5x/24=1,2*(25/30)^2
5x/24=1,2*(5/6)^2
5x/24=1,2*25/36
5x/24=5/36
5x*36=5*24
180x=120
x=120/180
x=1,5