Question

EX 5 vaa rrrrroooog explicit

Answer 1

$(2- \frac{3}{2})^ {-5} : (- \frac{25}{100} )^8 * (-\frac{1}{2})^ {101} =  \\ (\frac{1}{2}) ^ {-5} : (-\frac{1}{4})^8 *  (-\frac{1}{2})^ {101} = \\ (\frac{1}{2}) ^ {-5} : (\frac{1}{2})^{16} *  (-\frac{1}{2})^ {101}=\\(\frac{1}{2}) ^ {-5-16} *  (-\frac{1}{2})^ {101}= \\ (\frac{1}{2}) ^ {-21} *  (-\frac{1}{2})^ {101} =\\ -  ( \frac{1}{2})^{-21+101} = \\ -  ( \frac{1}{2})^{80}$

b) a= 25/100 * b

(a+b)/2 =37,5 => a+b = 37,5*2= 75

a+b=75 = > a= 75-b (inlocuim in prima relatie si obtinem:)

75-b = 25/100 * b

75-b = b/4

75= b/4+b

75= 5b/4

5b= 300

b= 300:5

b=60

a= 75-60

a=15

$\sqrt{63} +2(\sqrt{14}:\sqrt{2} +5 ) -\sqrt{175} =  \\   \sqrt{63} +2(\sqrt{7} +5 ) -\sqrt{175} =\\ \sqrt{63} +2 \sqrt{7}+10 -\sqrt{175} =  \\ 3\sqrt{7}+2 \sqrt{7}+10 - 5 \sqrt{7} = \\ 5 \sqrt{7} +10 -5  \sqrt{7} = \\ 10$

deci apartine lui N ( multimea nr naturale)