Question

Ex 6 va rog
dau corana va rog mult

Answer 1

Răspuns:

a) 2(y+3)-4(x+1)=8    2y+3-4x-4-8=0

-4x+2y-11=0 /(-1)       4x-2y+11=0

b) 3(x+2y)-2(2x+y)=5      3x+6y-4x-2y-5=0

-2x+4y-5=0  /(-1)             2x-4y+5=0

c) 2(x+y+1)-3(y+2x+1)=0     2x+2y+2-3y-6x-3=0

-4x-y-1=0  /(-1)                    4x+y+1=0

d) 5(x-y+1)=4(x+y+2)    5x-5y+5=4x+4y+8

x-9y-3=0

e) $\frac{x+3}{2} +\frac{y-4}{3} =\frac{x+3y+1}{6}$  /·6        3(x+3)+2(y-4)=x+3y+1

3x+9+2y-8-x-3y-1=0                  2x-y=0

f) $\frac{x+y-1}{3} +\frac{x-y+2}{2}=1\frac{1}{6}$         $\frac{x+y-1}{3} +\frac{x-y+2}{2}=\frac{7}{6}$ /·6  

2(x+y-1)+3(x-y+2)-7=0         2x+2y-2+3x-3y+6-7=0

x-y-3=0

Explicație pas cu pas: