Question

Ex ăsta vă rog….. vreau rezolvare completă…

Answer 1

Răspuns:

Explicație pas cu pas:

$\frac{1}{z} = \frac{1}{1+i} = \frac{1-i}{((1+i)(1-i)} = \frac{1-i}{1-i^{2} } = \frac{1-i}{2} }$

Answer 2

$\it \dfrac{1}{z}=\dfrac{^{1-i)}1}{\ \ 1+i}=\dfrac{1-i}{(1-i)(1+i)}=\dfrac{1-i}{1-i^2}=\dfrac{1-i}{1-(-1)}=\dfrac{1-i}{1+1}=\dfrac{1-i}{2}$