Question

ex incercuite......................

Answer 1

[tex] 48)~~\frac{2}{3}+ \frac{4}{5}= \frac{10}{15}+ \frac{12}{5}=\frac{22}{15} \\ 49)~~\frac{1}{2}- \frac{1}{6}+0,(6) =\frac{1}{2}- \frac{1}{6}+\frac{2}{3}=\frac{3}{6}- \frac{1}{6}+\frac{4}{6}=\frac{6}{6}=1 \\ 50)~~(0,5)\cdot \frac{2}{3} = \frac{1}{2} \cdot \frac{2}{3} = \frac{1}{3} \\ 51)~~1:(-0,5)=-1: 0,5 = -1 : \frac{1}{2} = -1 \cdot \frac{2}{1}=2 \\ 52)~~(- \frac{1}{2})^2 = ( \frac{1}{2})^2 = \frac{1}{2^2} =\frac{1}{4} \\ 53)~~2^{-2}\cdot 4 = \frac{1}{2^2} \cdot 4 =\frac{1}{4} \cdot 4 = 1[/tex]


[tex]54)~~x+2= \frac{1}{2}~~ =\ \textgreater \ ~~x = \frac{1}{2}-2 = -\frac{3}{2} \\ 55)~~2x-1=0 ~~ =\ \textgreater \ ~~x = \frac{1}{2} \\ 56)~~ x:(0,5) = 1 ~~ =\ \textgreater \ ~~x=1 \cdot 0,5 = 0,5 \\ 57)~~3(2x+1)=1~~ =\ \textgreater \ ~~ 6x+3=1~~ =\ \textgreater \ ~~x = \frac{1-3}{6}= -\frac{1}{3} \\ 58)~~(2+ (-1) + \frac{1}{2} ):3= \frac{2-1+0,5}{3} =\frac{1,5}{3} =0,5 \\ 59)~~ \frac{2 \cdot 2 + 3 \cdot 3 }{2+3}=\frac{4 + 9}{5}= \frac{13}{5}[/tex]