Question

Ex nr 2 va rog este urgent​

Answer 1

$a = 4 + |3 \sqrt{2} - 4| = 4 + 3 \sqrt{2} - 4 = 3 \sqrt{2}$

$b = \sqrt{20}$

$a = 3 \sqrt{2} = > (3 \sqrt{2} ) {}^{2} = 9 \times 2 = 18$

$b = \sqrt{20} = > ( \sqrt{20} ) {}^{2} = 20$

$18 < 20 = > a < b$