Question

exercitiile 5 si 6 va rog urgent

Answer 1

5) f²(x) =f(x)*f(x)
adica f²(x)=$\frac{9*(x+1)}{x+3}$ =$\frac{9x+9}{x+3}$

f²(x) -9 =$\frac{9x+9}{x+3}$ -9 =$\frac{9x+9}{x+3}$-$\frac{9x+27}{x+3}$  =$\frac{-18}{x+3}$

                -------
6)f(1/2)=√$\frac{45}{4}$   $\frac{3}{2}$ *√5
 
 f(-1/2)=√$\frac{13}{4}$ =$\frac{ \sqrt{13} }{2}$
 
 => f(1/2) > f(-1/2)