Question

Exercitiile 8 si 9. Rog seriozitate. Mersi :) ​

Answer 1

8.a)2x-5(x+3)+4=6x+24-2(x-1)-18=>

=>2x-5x-15+4=6x+24-2x+2-18=>

=>-3x-11=4x+24-16=>-3x-11=4x-8=>-3x-4x=-8+11=>

=>-7x=3=>-x=3/7=>x=-3/7

b) 1/2•{1/2•[1/2•(1/2x-1(amplificam cu 2)-1]-1}-1=0

1/2•{1/2•[1/2•(x-2/2)-1]-1}-1=0

1/2•[1/2•(x-2/4-1(amplificam cu 4)-1]-1=0

1/2•[1/2•(x-2-4/4)-1]-1=0

1/2•(1/2•x-6/4-1)-1=0

1/2•(x-6/8-1(amplificam cu 8)-1=0

1/2•(x-6-8)-1=0

1/2•(x-14)-1=0

x/28-1(amplificam cu 28)=0

x- 28/28=0

x/28=28/28

x/28=1

x=28

c) 5x-7/2(amplificam cu 3) - 2x+7/3(amplificam cu 2) =3x-14(amplificam cu 6)

3(5x-7) -2(2x+7) =6(3x-14)

15x-21-4x-14=18x-84

11x-35=18x-84

11x-18x=-84+35

-7x=-49

x=7

Answer 2

Răspuns:

Explicație pas cu pas: