Question

exercitiu 37 va rog dau coroana​

Answer 1

a) f'(x)=3x²+e× ≥ 0 ∀x∈R ⇒ f crescatoare pe R
b) f'(0)=3·0²+e$^{0}$ = 1
c) Ecuatia tangentei: y-f(0)=f'(0)(x-0)
f(0)=f'(0)=1, deci ecuatia tangentei este y-1=x, sau x-y=-1