Question

Exercițiu - clasa 8 a - proprietați de inegalitate

Dau: coroana, max puncte, multumesc, follow, 5 stele​

Answer 1

$a \geqslant \frac{2}{3} \\ 9a \geqslant \frac{9 \times 2}{3} = \frac{18}{3} = 6 \\ b \geqslant - \frac{3}{2} \\ 4b \geqslant - \frac{4 \times 3}{2} = - 6 \\ 9a + 4b \geqslant 6 +( - 6) = 6 - 6 = 0$

Answer 2

Explicație pas cu pas:

$a \geqslant \dfrac{2}{3} \ \ \Big| \cdot 9 \\ \implies 9a \geqslant 6$

$b \geqslant - \dfrac{3}{2} \ \ \Big| \cdot 4 \\ \implies 4b \geqslant - 6$

$9a + 4b \geqslant 6 + ( - 6) = 6 - 6 = \bf 0$