Question

exercitiu de prosti dar am nevoie de rezolvare. multumesc anticipat.

Answer 1

$\lim_{x \to 1} \frac{x-1}{x^2-1}= \lim_{x \to0} \frac{x-1}{(x-1)(x+1)}= \lim_{x \to0} \frac{1}{x+1}= \frac{1}{1+1}= \frac{1}{2}.$