Question

Exercitiul 10 b o sa dau coroana

Answer 1

ex 10)

b)

${9}^{29} = ( {3}^{2} ) {}^{29} = {3}^{58}$

${27}^{19} = ({3}^{3}) {}^{19} = {3}^{57}$

${3}^{58} > {3}^{57} = > {9}^{29} > {27}^{19}$