Question

exercitiul 13 a) si c)

Answer 1

a) <) AOB = 180° (1)

<) AOB = <) AOC + <) COB = 3x +x (2)

din (1) si (2) => 4x =180° | :4

=> x = 45°

c) <) AOB = <) AOC + <) COD + <) DOB

dar <) AOB = 180° =>

=> 180° = 102° +2x + x |- 102°

3x = 78° | : 3

x = 26°

Answer 2

Explicație pas cu pas:

A, O, B sunt coliniare

a)

$3x + x = 180 \degree \iff 4x = 180 \degree \\ x = 180 \degree : 4 \implies x = 45 \degree$

c)

$102 \degree + 2x + x = 180 \degree \\ 3x = 180 \degree - 102 \degree \iff 3x = 78 \degree \\ x = 78 \degree : 3 \implies x = 26 \degree$