Question

Exercițiul 13 și 14
Help!

Answer 1

13. (x-1)^2+(y-2)^2=0
(x-1)^2=0=>x-1=0
x=1
y-2=0=>y=2
1+2=3
3=3

14.(a+2)^2+(b-1)^2=0
a+2=0=>a=-2
b-1=0=>b=1
(a+b)^100+b^100
1+1
2

Sper ca te-am ajutat!!
Mult succes!!

Answer 2

Ex.13

(x-1)^2+(y-2)^2=0 x+y=0

(x-1)^2=0 x-1=0

(y-2)^2=0 y-2=0

{(0+3);(1+2);(2+1);(3+0)}=3

(x;y)={(0+3);(1+2);(2+1);(3+0)}

______________________

(1-1)^2=0^2=0 x=1

(2-2)^2=0^2=0 y=2

1+2=3

Ex.14

(a+2)^2+(b-1)^2=0 (a+b)^100+b^100

(a+2)^2=0 a+2=0

(b-1)^2=0 b-1=0

___________________

(-2+2)^2=0^2=0 a=-2

(1-1)^2=0^2=0 b=1

(-2+1)^100+1^100=(-1)^100+1^100=1+1=2

Succes!!!