Question

Exercitiul 15 va rog mult!!!Multumesc anticipat.+Dau coroanaaaa

Answer 1

$a) \sqrt{3} + 2 \sqrt{27} - \sqrt{75} = \\ \\ \sqrt{3} + 2 \times 3 \sqrt{3} - 5 \sqrt{3} = \\ \\ \sqrt{3} + 6 \sqrt{3} - 5 \sqrt{3} = \\ \\ 2 \sqrt{3}$

$b) \sqrt{44} + 5 \sqrt{99} - 3 \sqrt{11} - \sqrt{275} = \\ \\ 2 \sqrt{11} + 5 \times 3 \sqrt{11} - 3 \sqrt{11} - 5 \sqrt{11} = \\ \\ 2 \sqrt{11} + 15 \sqrt{11} - 3 \sqrt{11} - 5 \sqrt{11} = \\ \\ 9 \sqrt{11}$

$c) - 3 \sqrt{20} + \sqrt{80} - \sqrt{405} = \\ \\ - 3 \times 2 \sqrt{5} + 4 \sqrt{5} - 9 \sqrt{5} = \\ \\ - 6 \sqrt{5} + 4 \sqrt{5} - 9 \sqrt{5} = \\ \\ - 11 \sqrt{5}$

$d) \sqrt{32} - \sqrt{8} + \sqrt{98} - 5 \sqrt{18} = \\ \\ 4 \sqrt{2} - 2 \sqrt{2} + 7 \sqrt{2} - 5 \times 3 \sqrt{2} = \\ \\ 4 \sqrt{2} - 2 \sqrt{2} + 7 \sqrt{2} - 15 \sqrt{2} = \\ \\ - 6 \sqrt{2}$

$e) \sqrt{24} - 3 \sqrt{54} + \sqrt{600} = \\ \\ 2 \sqrt{6} - 3 \times 3 \sqrt{6} + 10 \sqrt{6} = \\ \\ 2 \sqrt{6} - 9 \sqrt{6} + 10 \sqrt{6} = \\ \\ 3 \sqrt{6}$

$f) - 3 \sqrt{28} + 2 \sqrt{700} + \sqrt{448} = \\ \\ - 6 \sqrt{7} + 20 \sqrt{7} + 8 \sqrt{7} = \\ \\ - 6 \sqrt{7} + 20 \sqrt{7} + 10 \sqrt{7} = \\ \\ (-6+20+8) \sqrt{7} = \\ \\ 22 \sqrt{7}$