Question

Exercitiul 16.....................................................

Answer 1

a)18(√3-2√2)+15(2√3-3√2)-7(3√3-√2)=
   =18√3-2√2+15·2√3-3√2-7·3√3-√2=
   =-16√6+30√3-3√2-21√3-√2=
   =14√6-2√2-21√3=
   =-9√6

b)5(4√3-3√5)-7(2√3+4√5)+2(3√3+6√5)=
   =5·4√3-3√5-7·2√3+4√5+2·3√3+6√5=
   =20√3-3√5-14√3+ 4√5+6√3+6√5=
   =36√15-3√5-14√3=
   =19√15

c)(18√2-24√3):6+2(4√3-3√2)-(30√3+15√2):5=
   =-6√6:6+2·4√3-3√2-30√3-15√2:5=
   =-6√6:6+8√3-3√2-30√3-15√2:5=
   =-6√6:6+5√6-30√3-15√2:5=
   =-6√6:6-40√6:5=