Question

Exercitiul 16 , vă rog . :)

Answer 1

x(2x-5) / 7 = (2-x) /3      se reduc fractiile
6x-15 = 14- 7x
13 x = 29
x= 29/13

(4x+1)/3 = (x-5)/4
16x+4=3x-15
13x=-19
x= -19/13

1/2+(2x-5)/4=x
2+2x - 5 = 4x
2x=-3
x=-3/2

(7x-5)/3 = (4x+1)/2
14x-10=12x+3
2x=13
x=13/2

1+(x-2)/4=(2x+5)/2
4+x-2=4x+10
-3x=8
x=-3/8

x/5-(4-x)/10 = (x+3)/2
2x-4+x=5x+15
3x=-19
x=-19/3

(4x-5)12=(x+1)/4-x/6
4x-5=3x+3 -2x
3x=8
x=8/3

punctele f si i nu se vad bine cifrele spre cotorul cartii
daca poti sa le redai in scris le voi  rezolva