Question

exercitiul 2
va rog mult
dau coroana + ma abonez ​

Answer 1

Δ=b²-4ac=64-16=48;

$\\\sqrt{48}=\sqrt{4*12}=2\sqrt{12}=2\sqrt{4*3}=4\sqrt{3} \\a_{1,2} =\frac{-b+\sqrt{delta}}{2a} =>a_{1} =\frac{8+4\sqrt{3} }{8} / dam-factor-comun-pe-4\\=>a=\frac{4(2+\sqrt{3} )}{8} =\frac{2+\sqrt{3} }{2} .$