Question

Exercitiul 24 , va rog

Answer 1

Răspuns:

a=24

b=6

Media aritmetica 15

Media geometrica 12

Explicație pas cu pas:

ridicand la patrat scapam de cate un radical, si desfacem parantezele:

ne ramane  a=sqrt(5)-sqrt(3)+sqrt(5)-sqrt(3)+2(sqrt(5)+sqrt(3))+24-4sqrt(5)

sqrt(5)+sqrt(5)+2(sqrt(5))-4(sqrt(5))=0

-sqrt(3)-sqrt(3)+2sqrt(3)=0

si ne ramane a=24

La B, utilizand formula a^2-2ab+b^2

formam patrate sub radical, si scapam de radical

Astfel ne ramane

b=sqrt(5)-1+1+sqrt(5)+2(3-sqrt(5))

-1+1=0 si desfacem parantezele, astfel ramane

sqrt(5)+sqrt(5)+6-2(sqrt(5))

sqrt(5)+sqrt(5)-2(sqrt(5))=0

Rezulta ca b=6

Media aritmetica (24+6)/2=15

Media geometrica sqrt(24*6,2)=12

//radical de ordinul 2 din 144

//sqrt(144)=12