Question

Exercitiul 3 va rog....

Answer 1

-formula chimica generala a alcoolului   CnH2n+2O  
-are masa molara M= 12n +2n+2+16=> 14n+18g/mol
-calculez masa de C din Co2
(12gC+2x16gO)CO2...........12gC
35,2g...................................m=9,6g
-calculez n
in 14n+18 galcool.................14n gC.    
 18,4g.....................................9,6g----> .n=  2---> C2H6O alcool etilic
M,alcool= (2x12gC+6gC+16gO)/MOL=46g/mol
-reactia de ardere
C2H6O+ 3O2---> 2CO2 +3H2o
46g..........3x22,4l
18,4g............V=26,88L O2
V.aer= 5x 26,88l=134,4 l