Question

Exercițiul 3 va rog.(Dau coronița)

Answer 1

$a)8 \sqrt{54} - 7 \sqrt{384} - 6 \sqrt{96} + 5 \sqrt{216} + 4 \sqrt{150} = 8 \times 3 \sqrt{6} - 7 \times 8 \sqrt{6} - 6 \times 4 \sqrt{6} + 5 \times 6 \sqrt{6} + 4 \times 5 \sqrt{6} = 24 \sqrt{6} - 56 \sqrt{6} - 24 \sqrt{6} + 30 \sqrt{6} + 20 \sqrt{6} = - 6 \sqrt{6}$

$b) \frac{1}{ \sqrt{12} } + \frac{1}{ \sqrt{75} } - \frac{3}{10 \sqrt{3} } = \frac{1}{2 \sqrt{3} } + \frac{1}{5 \sqrt{3} } - \frac{3}{10 \sqrt{3} } = \frac{ \sqrt{3} }{2 \times 3} + \frac{ \sqrt{3} }{5 \times 3} - \frac{3 \sqrt{3} }{10 \times 3} = \frac{ \sqrt{3} }{6} + \frac{ \sqrt{3} }{15} - \frac{3 \sqrt{3} }{30} = \frac{ \sqrt{3} }{6} + \frac{ \sqrt{3} }{15} - \frac{ \sqrt{3} }{10} = \frac{4 \sqrt{3} }{30} = \frac{2 \sqrt{3} }{15}$