Question

Exercițiul 4 va rog.

Answer 1

$3^{x+1}= \frac{ 3^{x-1}+5*3^x+1 }{2} \\ 2*3^x*3=3^x* \frac{1}{3}+5*3^x+1 \\ 3^x(6- \frac{1}{3}-5)=1 \\ 3^x= \frac{3}{2} \\ x= log_{3} \frac{3}{2}$

Answer 2

succes!----------------------------------------------------------------------------------------