Question

Exercițiul 4 va rog este urgent !!!!!!

Answer 1

E ( x ) =

$( \frac{x + 4}{x - 3} - \frac{x - 11}{ {x}^{2} - 6x + 9} ) \div (1 + \frac{4}{x - 3} )$

$( \frac{x + 4}{x - 3} - \frac{x - 11}{(x - 3) ^{2}}) \div \frac{x - 3 + 4}{x - 3}$

$\frac{(x - 3)(x + 4) - (x - 11)}{(x - 3) ^{2} } \div \frac{x + 1}{x - 3}$

$\frac{ {x}^{2} + 4x - 3x - 12 - x + 11}{(x - 3)^{2} } \times \frac{x - 3}{x + 1}$

$\frac{ {x}^{2} + 0 - 1}{x - 3} \times \frac{1}{x + 1}$

$\frac{(x - 1)(x + 1)}{x - 3} \times \frac{1}{x + 1}$

simplifici x+1 cu x+ 1

$\frac{x - 1}{x - 3}$