Question

exercițiul 6
dau coroana

Answer 1

[tex]a)\\(3\frac{1}{2}-\frac{1}{2})+(1\frac{1}{3}-\frac{1}{3})=3+1=4\\ b)\\\frac{3}{14}(\frac{7}{3}+\frac{10}{3}\cdot\frac{21}{10})=\frac{3}{14}(\frac{7}{3}+^{3) }7)=\frac{3}{14}\cdot\frac{28}{3}=2\\ c)\\3:(2\frac{21}{28}-1\frac{15}{28})+\frac{2}{3}\cdot\frac{2}{3}=\\ 3:1\frac{6}{28}+\frac{4}{9}=\\3:\frac{34}{28}+\frac{4}{9}=\\ 3\cdot\frac{28}{34}+\frac{4}{9}=^{9)}\frac{42}{17}+^{17)}\frac{4}{9}=\\ \frac{378+68}{153}=\\ \frac{446}{153} [/tex]

Answer 2

A)(7/2-1/2)+(9/8-1/3)
3+19/24
91/24
B)3/14•(7•1/3+10/3•21/10)
3/14•(7/3+7)
3/14•28/3
2
C)3:(13/5-43/28)+2/3•2/3
3:149/140+4/9
420/149+4/9
4376/1341
Deci / înseamnă bara de fracție
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