Question

Exercitiul 8. Mulţumesc anticipat!

Answer 1

Presupunem log_2 7 ∈ Q
log_2 7 = $\frac{a}{b}$ => 7 = $2^{ \frac{a}{b} }$ => $7^{b}$ = $( 2^{ (\frac{a}{b})b })$ => $7^{b} = 2^{a}$ - Acest lucru contrazice ca log_2 7 ∈ Q => log_2 7 ∉ Q

Si lucrezi la fel si la celalat exercitiu.