Question

Exercitiul este in atasament. Multumesc anticipat!!

Answer 1

a=log(5)(2) si b=log(5)(3)

A=log(15)(240)= log(5)(240): log(5)(15)

A=log(5)(3·5·16) : log(5)(3·5)

A= [log(5)(3)+ log(5)(5)+ log(5)(16)]:[log(5)(3)+log(5)(5)]

A=(b+1+4a):(b+1)

A=1+[4a/(b+1)]