Question

Exercițiul este în poza

Answer 1

Răspuns:

Explicație pas cu pas:

c) 33√5-7·{√2+[15√5-3(√5-4√2)]:12}=33√5-7·{√2+[15√5-3√5+12√2]:12}=

33√5-7·{√2+[12√5+12√2]:12}=33√5-7·{√2+√5+√2}=33√5-7·{2√2+√5}=

=33√5-14√2-7√5=33√5-14√2-7√5=26√5-14√2

d) 4√6+2√2·[6√2-2(3√2-2√3)]= 4√6+2√2·[6√2-6√2+4√3]= 4√6+2√2·4√3=4√6+8√6=12√6

e) 16+3√7·[21√3-3(7√3+2√7)]= 16+3√7·[21√3-21√3-6√7]= 16+3√7·(-6√7)=

16-18·(√7)²=16-18·7=16-126=-110

f) 13√2+2·{15√3-3[12√2-5(√2-√3)]}=13√2+2·{15√3-3[12√2-5√2+5√3]}=

13√2+2·{15√3-3[7√2+5√3]}=13√2+2·{15√3-21√2-15√3]}=13√2+2·{-21√2}=

13√2-42√2=-29√2        

g) 180√5+4√5{18√2-3√5[8√10-3(2√10-√5)]}=                                    

180√5+4√5{18√2-3√5[8√10-6√10+3√5]}=

180√5+4√5{18√2-3√5[2√10+3√5]}=180√5+4√5{18√2-6√50-9√25}=

180√5+4√5{18√2-6·5√2-9·5}=180√5+4√5{18√2-30√2-45}= 180√5+4√5{-12√2-45}=180√5-48√10-180√5=-48√10