Question

Exercitiul incercuit, va rog! Pas cu pas :)

Answer 1

6. a) [tex] \frac{10 x^{2}+4x }{25 x^{2} -4} = \frac{2x(5x+2)}{(5x-2)(5x+2)} = \frac{2x}{5x-2} ; [/tex]

b)$\frac{16 x^{2} -1}{16 x^{2} -4x} = \frac{(4x-1)(4x+1)}{(4x-2)(4x+2)}$

c)[tex] \frac{36- x^{2} }{2 x^{2} +12x} = \frac{(6-x)(6+x)}{2x(x+6)} = \frac{6-x}{2x} ; [/tex]

d)$\frac{35 x^{2} +15x}{49 x^{2} -9} = \frac{5x(7x+3)}{(7x-3)(7x+3)} = \frac{5x}{7x-3} ;$