Question

Exercițiul Nr 3.....

Answer 1

a)a+b-c=7/12        b)a+b-c=1/4    

a)a-(b-c)=5/12       b)a-(b-c)=-7/12

a)-(a-b)-c=-5/12     b)-(a-b)-c=-3/12

a)-(a+b)-(a-c)=5/12 b)-(a+b)-(a-c)=3/12

a=1/2;b=1/3;c=1/4.

a=-1/6;b=1/3;c=-1/12

a=-3;b=-0,5

1/2+1/3-1/4=6/12+4/12-3/12=(6+4-3)/12=7/12

-1/6+1/3-(-1/12)=-1/6+1/3+1/12=-2/12+4/12+1/12=2/12+1/12=3/12=1/4

1/2-(1/3-1/4)=1/2-(4/12-3/12)=1/2-1/12=6/12-1/12=5/12

-1/6-[1/3-(-1/12)]=-1/6-(1/3+1/12)=-2/12-(4/12+1/12)=-2/12-5/12=-7/12

-(1/2-1/3)-1/4=-(3/6-2/6)-1/4=-1/6-1/4=-2/12-3/12=-5/12

-(-1/6-1/3)-(-1/12)=-(-1/6-2/6)-(-1/12)=-3/6+1/12=-4/12+1/12=-3/12

-(1/2+1/3)-(1/2-1/12)=-(6/12+4/1)-(6/12-1/12)=10/12-5/12=5/12

-(-1/6+1/3)-[-1/6-(-1/12)]=-(-2/12+4/12)-(-1/6+1/12)=-2/12-(-2/12+1/12)=-2/12+1/12=3/12