Question

Explicati modulul:
a) |1-√7};
b) |-√3-√2|;
c) |8-√49|;
d) | (3-√2)la patrat |.
ajutatima pleasee

Answer 1

$a)\quad |1-\sqrt7| = \sqrt7-1,\quad ( deoarece \sqrt7\ \textgreater \ 1) \\ \\b)\quad |-\sqrt3-\sqrt2| = \sqrt3+\sqrt2\\ \\ c)\quad |8-\sqrt{49}| = |8-7| = |1| = 1\\ \\ d)\quad \underset{(3-\sqrt2)^2\geq0}{\underbrace{\Big|(3-\sqrt2)^2}}\Big| =(3-\sqrt2)^2 = 9-6\sqrt2+2 = 11-6\sqrt2$