Question

exprimati in grame:
2 moli hidroxid de calciu *Ca(OH)2*
4 moli de carbonat de magneziu *MgCO3*

ajutor va rog raman corigenta

Answer 1

Răspuns:

Ca = 40 g/mol

O = 16 g/mol

H = 1 g/mol

Mg = 24 g/mol

C = 12g/mol

a) 40 g/mol + 2× 16 g/mol + 2× 1 g/mol = 40 g/mol + 32 g/mol + 2 g/mol = 74 g/mol

2 moli de hidroxid de calciu = 2 × 74g = 148 g (pe 2 moli)

b) 24 g/mol + 12 g/mol + 3× 16g/mol = 84 g/mol

4 moli de carbonat de magneziu = 4 × 84g = 336g (pe 4 moli)

Explicație:

Sper ca te am ajutat!

Answer 2

Ca=40g/mol

O =16g/mol

H=1g/mol

Mg=24g/mol

C=12g/mol

Sper ca te-am ajutat<3