Question

f) 4•(8³-12)+10⁵=?
(3⁵+11²)•10-19=?

VA ROG NISTE RASPUNSURI NORMALE DE CLASA A 5-A.DAU COROANA ​

Answer 1

Răspuns:

4×(512-12)+10'5= 4×500+100000=102000

(243+121)×10-19= 364×10-19=3640-19=3621

Answer 2

Răspuns:

4•(8³-12)+10⁵=

1)8³-12=8•8•8-12=51-12=29

2)29•4=116

3)116+10⁵=116+10•10•10=116+1000=1116