Question

f:R-> R ; f (3x+2) =x (la a doua) +3x-1. Sa se calculeze f (3) , f (1) ; f (-1) , f (x)

Answer 1

f(3x+2) = x^2  +  3x  -  1

a) 3x+2=3, x= 1/3
    f(1/3) = 1/9 +1 -1 = 1/9

b) 3x+2=1, x= -1/3, f(-1/3) = 1/9 -1-1=1-18  /  9 = -17/9 = -1si8/9
c) 3x+2= -1, x= -1, f(-1) = 1-3-1= -3
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Succes in continuare!!!