Question

f:R->R
f(x)=$x^{2} - 4x - 12$

Answer 1

[tex]\text{Calculam intersectia cu axele de coordonate:}\\ f(x)=0\\ x^2-4x-12=0\\ (x+2)(x-6)=0\Rightarrow x\in \{-2,6\}\\ \\ f(0)=-12\\ \text{Coordonatele varfului parabolei }V(x_v,y_v)\\ x_v=\dfrac{4}{2}=2\\ y_v=\dfrac{-64}{4}=-16\\ \Rightarrow V(2,-16)[/tex]
Iti las si o poza cu graficul functiei.