Question

 f:R->R f(x)=x^2+2x+m aflati m pentru care minimul functiei f(x)=2 

Answer 1

Minimul funcţiei de gradul 2 are coordonatele:

$M(-\frac{b}{2a},-\frac{delta}{4a})$

$f_{(x)}=2=> \frac{delta}{4a} = 2$

$delta = 4-4m$

=> $-\frac{4-4m}{4}=2=> m=\frac{8+4}{4}=3$