Question

f(x)'=3sinx-4cosx+2tgx-5ctgx

Answer 1

sinx derivat=cosx
cosx derivat = - sinx
tgx derivat=$\frac{1}{cos ^{2}x }$
ctgx derivat=$\frac{-1}{sin ^{2}x }$

=3cosx+4sinx+$\frac{2}{cos ^{2}x }$+$\frac{5}{sin ^{2}x }$