Question

fie a=11/2 radical 3+1; b=radical 24:radical 2+1 sa se calculeze :
a) media aritmetrica a lui a,b;
b)media geometrica a lui a,b;
c) a la 2-b la 2
d)a-b+2ab
dau coroana si 15 pct

Answer 1

[tex]a= \frac{11}{2} * \sqrt{3+1} =\frac{11}{2} * \sqrt{4} =\frac{11}{2}*2=11 \\ b= \sqrt{24} : \sqrt{2+1}= \sqrt{24} : \sqrt{3} = \sqrt{8} = 2\sqrt{2} \\ ma_{(a,b)} = \frac{a+b}{2} = \frac{11+2 \sqrt{2} }{2} \\ mg_{(a,b)}= \sqrt{a*b} = \sqrt{11*2 \sqrt{2} } = \sqrt{22\sqrt{2} } \\ a^{2} - b^{2} =121-4*2=121-8=113 \\ a-b+2ab=11-2\sqrt{2}+2*11*2 \sqrt{2} =11-2 \sqrt{2} +44 \sqrt{2} = \\ =11+42 \sqrt{2} [/tex]