Question

Fie a,b,c trei numere naturale.Stiind ca mediile aritmetice a câte 2 dintre ele sunt 90,99 si 93 sa se afle numerele.

Answer 1

(a+b)/2=90
(b+c)/2=99
(a+c)/2=93
a+b=180
b+c=198
a+c=186
a=180-b
c=198-b
180-b+198-b=186
378-2b=186
378-186=2b
2b=192
b=192/2=96
a=180-96=84
c=198-96=102

Answer 2

(a+b)/2=90=>a+b=180=>a=180-b
(b+c)/2=99=>b+c=198
(a+c)/2=93=>a+c=186=>a=186-c

Egalam,cele,doua,expresii,ale,lui,a
180-b=186-c
180-b-186+c=0
-6-b+c=0
c-b=6=>c=6+b
Stim,ca,c+b=198
6+b+b=198
2b=192
b=96
c=102
a=84