Question

Fie a=radiacal 125 - radical 5 ,iar b=radical(4radical din 5 -8)totul la a doua,determinati media aritmetica

Answer 1

 [tex]a=5\sqrt5-\sqrt5=4\sqrt5\;;\;\\ b=\sqrt{(4\sqrt5-8)^2}=4\sqrt5-8\;;\\ m_a=\frac{4\sqrt5\;+\;4\sqrt5-8}{2}=\frac{8\sqrt5-8}{2}=4(\sqrt5-1)\;; [/tex]