Question

Fie a=
$(\frac{2}{ 3}) {}^{n} \div \frac{2 {}^{n + 1} + 6 {}^{n +1 } } {3 {}^{n + 1} + 9 {}^{n + 1} }$
Unde n € N
Calculati
$(\frac{2a}{3}) {}^{100}$

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Answer 1

O varianta de rezolvare