Question

Fie conul circular drept in care G=25 cm si Ab=400π aflati : R , h , Al , At si V =? Dau coronița

Answer 1

G=25 cm

Ab=πR²
400π=πR²/:π
R²=400
R=√400
R=20 cm

BD=DC=20 cm ( pt ca sunt raze)

BC=2*20cm
BC=40 cm

In ΔADB dr in D cu T.P ⇒ i²=c1²+c2² ⇔
⇔ 25²=h²+20² ⇒
⇒625=h²+400 ⇒
⇒h²=625-400 ⇒
⇒h²=225 ⇒
⇒h=√225 ⇒
⇒h=15 cm

Al=πRG
Al=π*20cm*25cm
Al=500πcm²

At=πR(G+R)
At=π20(25+20)
At=π20*45
At=900πcm²

V=πR²*h/3
V=π20²*15/3
V=π400*15/3
V=2000πcm³


Sper ca te am ajutat!!!