Question

fie E(x)=1-x+5supra x+2 ori x+2 supra x-2 unde x este nr real

Answer 1

E(x)=1-x+5 /x+2 *x+2/x-2 simplifici x+2 cu x+2 dand E(x)=1-x+5/x-2 E(x)=6-x/x-2 rationalizam cu conjugatul lui x-2 care este x+2 dand E(x)=(6-×)(×+2)/(×-2)(×+2) E(x)=6×+12-ײ-2×/ײ-4 E(x)=4×+12-ײ/ײ-4

Answer 2

       
$E(x)=1- \frac{x-5}{x+2}* \frac{x+2}{x-2}=1- \frac{(x-5)(x+2)}{(x+2)(x-2)} \;\;\;Se \;simplifica\;(x+2) \\ E(x)=1-\frac{x-5}{x-2}=\frac{x-2}{x-2}-\frac{x-5}{x-2}=\frac{(x-2)-(x-5)}{x-2}=\frac{x-2-x+5}{x-2}= \boxed{\frac{3}{x-2}}$