Question

Fie f:R⇒R,f(x)=x²-3x+2. Aflati valoarea minima a functiei.

Answer 1

$Functie~de~gradul~2,~cu~a>0~(a=1),~deci~sigur~ai~un~minim.\\ \\ Minimul~este~varful~parabolei~cu~V(\frac{-b}{2a},-\frac{\Delta}{4a}).\\ \\ Adica~V(\frac{3}{2}, -\frac{1}{4}).\\ \\ Minimul~se~atinge~pentru~f(\frac{3}{2})=-\frac{1}{4} .\\ \\ To~sum~up,~minimul~este~\frac{-1}{4}.$

Answer 2

-b/2a=3/2

f(3/2)=9/4-9/2+2=2-9/4=(8-9)/4=-1/4 de astepta sa fie <0, pt ca Δ>0