Question

Fie functiile f:R->R, f(x)=x+3 si g:R->R, g(x)=2x-1. Sa se determine solutia reala a ecuatiei 2f(x)+3g(x)=-5

Answer 1

2f(x) + 3g(x)= -5
2(x+3) + 3(2x-1)=-5
2x+6+6x-3=-5
8x+3=-5
8x=-5-3
8x=-8
x=-8:8
x=-1 
S={-1}