Question

Fie G si G' centrele de greutate ale triunghiurilor ABC si MNP , unde A (0,1) B (2,2) C (7,0)  , M(-2,2) N (1,6) , P(-2,4) .Sa se calculeze distanta GG'. Urgent!

Answer 1

$x_{G} = \frac{0+2+7}{3} =3$
$y_G=1$
$x_ G^{'} =-1$
$y_G^{'}=4$
$GG ^{'} = \sqrt{(( -1-3)^{2} +(4-1)^{2}} = \sqrt{25}=5$