Question

Fie h inaltimea trapezului ABCD cu baza mare AB.Calculati ariile triunghiurilor ABC,ABD,ADC,DCB,daca:
AB=11 cm
CD=8 cm
h= 9 cm

Answer 1

    
[tex]\displaystyle A_{_{\Delta ABC} } = \frac{AB\times h}{2}= \frac{11\times 9}{2}=\frac{99}{2}=\boxed{49,5\,cm^2} \\ \\ A_{_{\Delta ABD} } = \frac{AB\times h}{2}= \frac{11\times 9}{2}=\frac{99}{2}=\boxed{49,5\,cm^2} \\ \\ A_{_{\Delta ADC} } = \frac{CD\times h}{2}= \frac{8\times 9}{2}=\frac{72}{2}=\boxed{36^2\,cm} \\ \\ A_{_{\Delta DCB} } = \frac{CD\times h}{2}= \frac{8\times 9}{2}=\frac{72}{2}=\boxed{36^2\,cm}[/tex]